How do you solve #2 ln x = 1#?

1 Answer
Lovecraft
Mar 7, 2016

#x=sqrt(e)#

Explanation:

Isolate the logarithm

#ln(x)=1/2#

#ln(x)# is the natural logarithm, i.e.: it has base #e#, so take the exponential of both sides to get rid of the log

#e^(ln(x))=e^(1/2)#
#x=e^(1/2)#

And there you go, if you prefer, you can remember that #a^(1/2) = sqrt(a)#, so you can also rewrite that to

#x=sqrt(e)#

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