How do you solve $5^(x+2) = 8.5$ ?

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Answer 1 · 2016-03-12T00:19:53

$x=log_5(0.34)$

$5^(x+2)=8.5$

If we apply logarithms, we obtain:

$x+2=log_5(8.5)$

$x=log_5(8.5)-2$

$x=log_5(8.5)-log_5(5^-2)$

$x=log_5(8.5/25)$

$x=log_5(0.34)$

or $x=ln(0.34)/ln(5)$

How do you solve 5^(x+2) = 8.55^(x+2) = 8.5?