How do you simplify $(-3i)(2i)$ ?

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Answer 1 · 2016-03-15T08:32:22

$(-3i)(2i)=6$

You have to compute the product as if it was a product of monomial
$(-3i)(2i)=-3*2*i*i=-6i^2$

Now $i$ is the imaginary unit Complex Number Plane

and it's true the following identity:

$i^2=-1$

$:.-6i^2=-6*(-1)=6$

How do you simplify (-3i)(2i)(-3i)(2i)?