Question

How do you find the polar coordinate of (-1,1)?

Answer 1

Polar coordinates are `(sqrt2,(3pi)/4)`

Explanation:

Polar coordinates `(r,theta)` of rectangular coordinates `(x,y)` are given by `r=sqrt(x^2+y^2)` and `theta=tan^(-1)(y/x)`.

Hence polar coordinates of `(-1,1)` are

`(sqrt((-1)^2+1^2),tan^(-1)((-1)/1))` or

`(sqrt((1+1)),tan^(-1)(-1))` or

`(sqrt2,(3pi)/4)`