How do you find the inverse of $y = 3 x^{2} - 2$ $y=3x^2-2$ and is it a function?

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How do you find the inverse of $y = 3 x^{2} - 2$ $y=3x^2-2$ and is it a function?

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Answer 1 · 2016-03-24T20:15:10

$y^{- 1} = \pm \sqrt{\frac{x + 2}{3}}$ $y^-1=±sqrt((x+2)/3)$

Explanation:

$y = 3 x^{2} - 2$ $y=3x^2-2$
$y + 2 = 3 x^{2}$ $y+2=3x^2$
$x^{2} = \frac{y + 2}{3}$ $x^2=(y+2)/3$
$x = \pm \sqrt{\frac{y + 2}{3}}$ $x=±sqrt((y+2)/3)$
$change x as y and y as x$ $"change x as y and y as x"$
$y^{- 1} = \pm \sqrt{\frac{x + 2}{3}}$ $y^-1=±sqrt((x+2)/3)$

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How do you find the inverse of $y = 3 x^{2} - 2$ $y=3x^2-2$ and is it a function?

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