How do you write the equation in point slope form given slope of -1/3 and passing through the point (6, -4)?

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Answer 1 · 2016-03-25T06:08:07

#x+3y+6=0#

the equation in point slope form slope of #-1/3# and passing through the point #(6, -4)#

By slope point form,

#(y-y_1)=m(x-x_1)#

#(y-(-4))=-1/3(x-6)#

#(y+4)=-1/3(x-6)#

#y+4=-x/3+2#

#y+x/3=2-4#

#(3y+x)/3=-2#

#3y+x=-2xx3#

#3y+x=-6#

#3y+x+6=0#

i.e. #x+3y+6=0#