How do you find the vertex and the intercepts for #f(x)=x^2+x-2#?
2 Answers
Explanation:
x-coordinate of vertex:
y-coordinate of vertex:
To find y-intercept, make x = 0 --> y = -2
To find x-intercepts, make t = 0, and solve the quadratic equation:
Since a + b + c = 0, use shortcut. The 2 x-intercepts (real roots) are:
1 and
x int:
y int:
Explanation:
In a quadratic equation like
So,
To find the
To find the