If $18 L$ of a gas at room temperature exerts a pressure of $64 kPa$ on its container, what pressure will the gas exert if the container's volume changes to $24 L$ ?

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If $18 L$ of a gas at room temperature exerts a pressure of $64 kPa$ on its container, what pressure will the gas exert if the container's volume changes to $24 L$ ?

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Answer 1 · 2016-03-30T04:02:35

$P_2 = 64 *18/24 = 3/4*64 = 48 kPa$

Explanation:

Given: Container with initial, $V_1 = 18L and P_1=64kPa$
Final $V_2= 24L$
Required: New Pressure
Solution Strategy: Straight application of Boyle's Law
$P_1V_1=P_2V_2; P_2=P_1V_1/V_2$ substituting the known values
$P_2 = 64 *18/24 = 3/4*64 = 48 kPa$

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If $18 L$ of a gas at room temperature exerts a pressure of $64 kPa$ on its container, what pressure will the gas exert if the container's volume changes to $24 L$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

If 18 L18 L of a gas at room temperature exerts a pressure of 64 kPa64 kPa on its container, what pressure will the gas exert if the container's volume changes to 24 L24 L?

1 Answer

Explanation:

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If $18 L$ of a gas at room temperature exerts a pressure of $64 kPa$ on its container, what pressure will the gas exert if the container's volume changes to $24 L$ ?