How do you solve #log(5x + 3) = 0#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Abhinav T. Mar 30, 2016 #-2/5# Explanation: #log(5x+3)=0# # or, e^(log(5x+3)) = e^0 # # or, 5x+3 = 1# Hence, # x = -2/5# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 2836 views around the world You can reuse this answer Creative Commons License