How do you solve $e^(5-9 x)=990$ ?

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Answer 1 · 2016-03-31T14:16:35

$x=(5-ln 990)/9$ .

If $e^m=n$ , inversely, m = ln n

Here, $e^(5-9x)=990$ . $m=5-9x, n=990$ .

Inversely, $5-9x=ln 990$ .

$9x = 5-ln 990$ .

$x=(5-ln 990)/9$ .

How do you solve e^(5-9 x)=990e^(5-9 x)=990?