Question

The gas inside of a container exerts `12 Pa` of pressure and is at a temperature of `250 ^o C`. If the temperature of the gas changes to `80 ^oK` with no change in the container's volume, what is the new pressure of the gas?

Answer 1

`1.836Pa` (4s.f.)

Explanation:

First convert temperature to Kelvin, `250+273=523K`

Ideal gas law: `P_1V_1=nRT_1`
Calculate for number of moles:
`n=(P_1V_1)/(RT_1)=(12V_1)/(8.314*523)=2.760times10^-3V_1`

Use Ideal gas law again:
`P_2V_2=nRT_2`
Since `V_2=V_1`:
`P_2V_1=2.760times10^-3V_1*8.314*80`
`V_1`s cancel to leave:
`P_2=2.760times10^-3*8.314*80=1.836Pa`