A container with a volume of #25 L# contains a gas with a temperature of #150^o K#. If the temperature of the gas changes to #320 ^o K# without any change in pressure, what must the container's new volume be?

Question

1318 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-02T13:23:13

#160/3L#

From Ideal Gas Equation; #PV=nRT#

Pressure, number of moles and Gas constant are all fixed.

#V=nRT/P# or #V/T=nR/P#

As long as pressure and the amount of gas remains unchanged, the ratio of #V# and #T# is always the same.

#V_1/T_1=V_2/T_2#
#(25L)/(150K)=(V_2)/(320K)#
#V_2=160/3L#