How do you solve #7^x = 30#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Shwetank Mauria Apr 8, 2016 #x=1.7478# Explanation: #7^x=30# means #x=log_7(30)#. Now as #log_ba=loga/logb# #x=log_7(30)=log30/log7=1.4771/0.8451=1.7478# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 4800 views around the world You can reuse this answer Creative Commons License