A container with a volume of $12 L$ $12 L$ contains a gas with a temperature of $150^{o} C$ $150^o C$ . If the temperature of the gas changes to $620^{o} K$ $620 ^o K$ without any change in pressure, what must the container's new volume be?

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A container with a volume of $12 L$ $12 L$ contains a gas with a temperature of $150^{o} C$ $150^o C$ . If the temperature of the gas changes to $620^{o} K$ $620 ^o K$ without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-04-09T11:18:33

new volume $\approx 17.6 L$ $~~17.6 L$

Explanation:

Because the pressure don't change
we apply $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$ $V_1/T_1=V_2/T_2$
where V (L), T(K)
Hence $\frac{12}{423} = \frac{V_{2}}{620}$ $12/423=V_2/620$
$V_{2} = 12 \cdot \frac{620}{423}$ $V_2=12*620/423$
$V_{2} \approx 17.6 L$ $V_2~~17.6 L$

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A container with a volume of $12 L$ $12 L$ contains a gas with a temperature of $150^{o} C$ $150^o C$ . If the temperature of the gas changes to $620^{o} K$ $620 ^o K$ without any change in pressure, what must the container's new volume be?

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A container with a volume of 12 L12L12 L contains a gas with a temperature of 150^o C150oC150^o C. If the temperature of the gas changes to 620 ^o K620oK620 ^o K without any change in pressure, what must the container's new volume be?

1 Answer

Explanation:

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A container with a volume of $12 L$ $12 L$ contains a gas with a temperature of $150^{o} C$ $150^o C$ . If the temperature of the gas changes to $620^{o} K$ $620 ^o K$ without any change in pressure, what must the container's new volume be?