How do you graph # (x+3)^2 + (y-2)^2 = 25#?
1 Answer
Centre Point at:
Radius of: 5
Explanation:
The function is a circular function:
The general form of a circular function can be expressed as:
Where the centre point of the graph is present at the point
and the solution (the number after the = sign) is the radius of the circle squared.
Therefore, from your function:
We can determine that:
The centre point of the function is present at the point
For any function,
Therefore, by substituting
By simplifying this and solving for
Remember that any real square has two solutions (a positive and negative), hence the
Therefore, two
One at:
The other at:
For any function,
Therefore, if we substitute
By simplifying and solving for
Again, remember that any real square has two solutions (a positive and negative), hence the
Therefore, two
One at:
The other at:
To summarise:
If we plot all of our points on the graph, we get:
Centre Point at:
Radius of: 5
graph{(x+3)^2+(y-2)^2=25 [-21.42, 18.58, -7.32, 12.68]}