Question

How do you find the vertex and axis of symmetry of `y=x^2+2x-1`?

Answer 1

see below

Explanation:

Axis of symmetric=`-b/(2a)`=`-2/(2(1))`=`-1`

To find value of y, substitute value of x into equation.

`y=(-1)^2+2(-1)-1`=`-2`

Vertex of symmetric is `(-1,-2)`