How do you solve $sqrt(4p+1)=2p-1$ ?

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Answer 1 · 2016-05-07T02:52:58

$p=0 or p=2$

First, square both sides of the equation.

$(sqrt(4p+1))^2 = (2p-1)^2$

$4p+1 = 4p^2-4p+1$

Move all terms to the same side so that one side of the equation is $0$ .

$0=4p^2-4p-4p+1-1$

Combine like terms.

$0=4p^2-8p$

Factorise a $4p$
$0=4p(p-2)$

$4p=0 or p-2 = 0$

$p= 0 or p=2$

How do you solve sqrt(4p+1)=2p-1sqrt(4p+1)=2p-1?