A triangle has sides A, B, and C. The angle between sides A and B is $\frac{π}{3}$ $(pi)/3$ and the angle between sides B and C is $\frac{π}{6}$ $pi/6$ . If side B has a length of 26, what is the area of the triangle?

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A triangle has sides A, B, and C. The angle between sides A and B is $\frac{π}{3}$ $(pi)/3$ and the angle between sides B and C is $\frac{π}{6}$ $pi/6$ . If side B has a length of 26, what is the area of the triangle?

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Answer 1 · 2016-05-19T03:09:17

$\frac{169 \sqrt{3}}{2}$ $(169sqrt3)/2$

Explanation:

The third angle $\frac{π}{2}$ $pi/2$ , which means it is a right angled triangle.
The three sides are $1 : \sqrt{3} : 2$ $1:sqrt3:2$ in length with side B being the longest. Side A is vertical to side C. Side A= $13$ $13$ , side C= $13 \sqrt{3}$ $13sqrt3$
Area of triangle= $\frac{1}{2} \cdot 13 \cdot 13 \sqrt{3} = \frac{169 \sqrt{3}}{2}$ $1/2*13*13sqrt3=(169sqrt3)/2$

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A triangle has sides A, B, and C. The angle between sides A and B is $\frac{π}{3}$ $(pi)/3$ and the angle between sides B and C is $\frac{π}{6}$ $pi/6$ . If side B has a length of 26, what is the area of the triangle?

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A triangle has sides A, B, and C. The angle between sides A and B is π3(pi)/3 and the angle between sides B and C is π6pi/6. If side B has a length of 26, what is the area of the triangle?

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A triangle has sides A, B, and C. The angle between sides A and B is $\frac{π}{3}$ $(pi)/3$ and the angle between sides B and C is $\frac{π}{6}$ $pi/6$ . If side B has a length of 26, what is the area of the triangle?