What is the vertex of the parabola $y = {(x - 8)}^{2}$ $y=(x-8)^2$ ?

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Answer 1 · 2016-05-30T07:28:16

Vertex is at point (8,0).

The parabola equation is of the form

$y = a (x - h) + k$ $y=a(x-h)+k$

The vertex is at point $(h, k)$ $(h,k)$

The given equation is

$y = {(x - 8)}^{2}$ $y=(x-8)^2$

So the vertex is at $(8, 0)$ $(8,0)$

graph{(x-8)^2 [-0.39, 17.02, -2.586, 6.114]}

What is the vertex of the parabola y=(x−8)2y=(x-8)^2?