How do you find the center of the radius of (x-4)^2 +y^2 =16(x−4)2+y2=16?

1 Answer
Joseph W.
Jun 2, 2016

Center: (4,0)

Radius=4

Explanation:

The circle formula is

(x-x_1)^2+(y-y_1)^2=r^2(x−x1)2+(y−y1)2=r2

The center of all circles is (x_1,y_1)(x1,y1), without the negative. The radius is the r. So we must square root the r^2r2 to find r, and it will be the positive square root as length must be positive.

So from the equation

(x-4)^2+(y^2)=16(x−4)2+(y2)=16

We can know the radius is +sqrt16=4+√16=4

The center is x_1, y_1x1,y1. x_1=4x1=4 and y_1=0y1=0.

y_1y1 is 0 as there must be a y co-ordinate of the center and the only number which allows (y-y_1)^2=y^2(y−y1)2=y2 is 0

Related questions
See all questions in Standard Form of the Equation
Impact of this question
5977 views around the world
You can reuse this answer
Creative Commons License