A triangle has sides with lengths of 6, 4, and 3. What is the radius of the triangles inscribed circle?

2 Answers
Jun 7, 2016

r=(pa)(pb)(pc)p with p=a+b+c2
r=0.820413

Explanation:

From Heron's formula, the area of a triangle giving their sides a,b,c is

A=p(pa)(pb)(pc) with p=a+b+c2

Let o be the triangle orthocenter, then the distance between each side and o is r which is the inscribed circle radius. So

A=a×r2+b×r2+c×r2 then
r(a+b+c2)=A=r×p

Finally

r=p(pa)(pb)(pc)p=(pa)(pb)(pc)p=0.820413

Jun 13, 2016

0.820

Explanation:

I created this figure using MS Excel

Suppose
AB=6
BC=4
CA=2

m+l=6 [1]
l+n=4 [2]
m+n=3 [3]

[3]-[2]
ml=1 [4]

[4]+[1]
2m=5 => m=52
l=72
n=12

Applying law of cosines:
AB2=BC2+CA22BCCAcos(AˆCB)
36=16+9243cos(AˆCB)
24cos(AˆCB)=11 => AˆCB117.28

tan(AˆCB2)=rn
r=12tan(117.282)=0.820