Question #950bd

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Question #950bd

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Answer 1 · 2016-06-20T21:45:36

It is both

Explanation:

Aspirin has a free carboxylic group (- $C O O H$ $COOH$ , top part) corresponding to the molecule of salycilic acid and an ester group (acetyl - $O C O C H_{3}$ $OCOCH_3$ , right part) formed by a molecul of acetic acid ( $H O C O C H_{3}$ $HOCOCH_3$ ) condensed with the ortho hydroxyl (- $O H$ $OH$ ) group of salycilic acid.

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Question #950bd

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