Question

How do you find the derivative of `6/(x^2 + 3)`?

Answer 1

`(-12x)/(x^2+3)^2`

Explanation:

By the definition of the quotient rule,
`((x^2+3)*6' - 6(2x))/(x^2+3)^2`

We know that the derivative of any integer is zero. So 6' would be zero.

Therefore, the derivative would be

`(-12x)/(x^2+3)^2`