How do you find the area of the triangle given a=28.16 cm, b=60.15 cm, c=51.17 cm?

Question

1577 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-27T06:08:09

#11.81016511# # Cm^2 #

Area of a triangle whose sides have lengths a, b, and c is

#A=sqrt {s(s-a)(s-b)(s-c)#

where s is the semiperimeter of the triangle; that is,

# s=(a+b+c)/2#

#s = (28.16 + 60.15 + 51.17)/2 # #= 69.74#

#A = sqrt (69.74* (69.74 - 28.16)*(69.74 - 60.15)*(69.74 - 51.17)#

#A = sqrt( 69.74*41.58*9.59*18.57)# = #11.81016511#