How do you solve 4−√3x+1=5 and find any extraneous solutions?

1 Answer
Daniel L.
Jun 29, 2016

This equation has no real solutions.

Explanation:

To solve such equation first we move roots to left side, and number to right side.

4−√3x+1=5

−√3x+1=1

√3x+1=−1

Now you can see that the equation has no real solutions because there are no real numbers whose square root (or any other root of an even degree) is negative.

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