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How do you simplify hyperbolic function $cosh (ln t)$ $cosh(lnt)$ ?

1 Answer

A. S. Adikesavan · Oscar L.

Jul 1, 2016

$\frac{1 + t^{2}}{2 t}$ $(1+t^2)/(2t)$ .

Explanation:

First use

$cosh x = \frac{e^{x} + e^{- x}}{2} = \frac{e^{x} + (\frac{1}{e^{x}})}{2}$ $cosh x=(e^x+e^(-x))/2=(e^x+(1/e^x))/2$ .

Then let $x = ln t$ $x=ln t$ and use $e^{ln t} = t$ $e^ln t=t$ .

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