How do you integrate #x(x^(2/3))dx#? Calculus Introduction to Integration Integrals of Polynomial functions 1 Answer Eddie · Alexander Jul 2, 2016 #= 3/8x^(8/3) # Explanation: #int \ x(x^(2/3)) \ dx# #= int \ x^(5/3) \ dx# #= 3/8x^(8/3) + C# Answer link Related questions How do you evaluate the integral #intx^3+4x^2+5 dx#? How do you evaluate the integral #int(1+x)^2 dx#? How do you evaluate the integral #int8x+3 dx#? How do you evaluate the integral #intx^10-6x^5+2x^3 dx#? What is the integral of a constant? What is the antiderivative of the distance function? What is the integral of #|x|#? What is the integral of #3x#? What is the integral of #4x^3#? What is the integral of #sqrt(1-x^2)#? See all questions in Integrals of Polynomial functions Impact of this question 4365 views around the world You can reuse this answer Creative Commons License
