How do you solve for x in #Lnx^2=4#?

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Answer 1 · 2016-07-11T11:02:38

#x ± e^2#

Taking the natural logarithm of both sides gives us

#cancel(e)^(cancel(ln)(x^2)) = e^(4)#

#x^2 = e^4#

Taking the square root of both sides yields

#x ± sqrt(e^4)#

Simplifying further then gives us our result of

#x ± e^2#