How do you graph the equation #r = 1 + cos( theta )#?
1 Answer
Graph of
graph{x^2+y^2=sqrt(x^2+y^2)+x [-10, 10, -5, 5]}
Explanation:
In case you are trying to graph the equation in rectangular form, here's a way to get it to rectangular form and graph it.
We can make use of the following formulas when trying to convert from polar to rectangular:
Now we can rewrite our equation:
Multiplying both sides by
#= r + rcos(theta)#
Substituting the value of
#=sqrt(x^2+y^2) + x#
So our equation becomes
Below are a few graphs.
Graph of
graph{x^2+y^2=sqrt(x^2+y^2)+x [-10, 10, -5, 5]}