Graphing Basic Polar Equations
Key Questions
-
Limacons are polar functions of the type:
r=a+-bcos(theta)
r=a+-bsin(theta)
With|a/b|<1 or1<|a/b|<2 or|a/b|>=2 Consider, for example:
r=2+3cos(theta)
Graphically:
Cardioids are polar functions of the type:
r=a+-bcos(theta)
r=a+-bsin(theta)
But with|a/b|=1 Consider, for example:
r=2+2cos(theta)
Graphically:
in both cases:
0<=theta<=2pi .....................................................................................................................
I used Excel to plot the graphs and in both cases to obtain the values in thex andy columns you must remember the relationship between polar (first two columns) and rectangular (second two columns) coordinates: -
You can find a lot of information and easy explained stuff in "K. A. Stroud - Engineering Mathematics. MacMillan, p. 539, 1970", such as:
If you want to plot them in Cartesian coordinates remember the transformation:
x=rcos(theta)
y=rsin(theta) For example:
in the first one:r=asin(theta) choose various values of the angletheta evaluate the correspondingr and plug them into the transformation equations forx and y . Try it with a program such as Excel... it is fun!!! -
You consider a function of the type:
r=f(theta) So you give values of the angle
theta and the function gives you values ofr .To graph polar functions you have to find points that lie at a distance
r from the origin and form (the segmentr ) an angletheta with thex axis.
Take for example the polar function:
r=3 This function describes points that for every angle
theta lie at a distance of 3 from the origin!!!Graphically:
The result is a circle of radiusr=3 .Now, the only complication is when
r becomes NEGATIVE ...how do I plot this?
We use a trick....we take the positive and flip it about the origin!!!!!!
Take for example the polar function:
r=-3 This function describes points that for every angle
theta lie at a distance of...-3 from the origin????
We use our trick!Graphically:
Every point of the old graph flipped about the origin!!!!
It is a circle...again!!!!Now try by yourself with:
r=2cos(theta)
Build a table oftheta andr and plot it...you should get another circle but with its center....on thex axis (in(1,0) ) and radius =1.There are more complicated (and graphically beautiful) polar functions such as limacons, cardioids, roses, lemniscates, etc…try them!!!