How do you graph r2=−cosθ?

2 Answers
Sam
May 12, 2016

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Explanation:

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Cesareo R.
May 12, 2016

The pass equations are:
x=r⋅cos(θ),y=r⋅sin(θ)
squaring them, x2=r2⋅cos(θ)2,y2=r2⋅sin(θ). Substituting now, x2=−cos(θ)⋅cos(θ)2,y2=−cos(θ)⋅sin(θ)2. Those equations make sense only for cos(θ)≤0 so for π≤θ≤2π. Having this in mind we can draw: x=±cos(θ)⋅√−cos(θ),y=±sin(θ)⋅√−cos(θ) for π≤θ≤2π

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