How do you graph the system of polar equations to solve r=2+2costheta and r=3+sintheta?

1 Answer
Feb 5, 2017

See the graph for your pair of a cardioid and a limacon. I have used Socratic utility. Common points are (2, -pi/2) and (3.79, 26.57^o).

Explanation:

Here, use cartesian forms of the equations :

For the cardioid, it is from

r^2=x^2+y^2=2r +2rcostheta=2sqrt(x^2+y^2)+2x

and, for the limacon, it is from

r^2=x^2+y^2=3r + rsintheta=3sqrt(x^2+y^2)+y

It is revealed that one common point is on

theta = -pi/2, at which r = 2.

We can measure the other angle or solve

r=2+2costheta=3+sintheta. This gives

cos(theta+cos^(-1)(2/sqrt5))=1/sqrt5, from which

cos(theta+26.57^0)=cos(63.43^o), and so,

theta=26.57^o^ and r = 3.79, nearly.

For the second point, use

theta+cos^(-1)(2/sqrt5)=2pi+cos^(-1)(1/sqrt5), giving

theta=360^o-(26.57^0+63.43^o)=270^o that is equivalent to

-90^o.

graph{(x^2+y^2-2sqrt(x^2+y^2)-2x)(x^2+y^2-3sqrt(x^2+y^2)-y)=0 [-10, 10, -5, 5]}