How do you graph $r = 5 - 5 cos θ$ $r=5-5costheta$ ?

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Answer 1 · 2018-04-18T09:21:26

As below.

Standard form of equation is $y = A cos (B x - C) + D$ $y = A cos (Bx -C) + D$

Given equation is $y = - 5 cos θ - 5$ $y = -5 cos theta - 5$

$A = - 5, B = 1, C = 0, D = - 5$ $A = -5, B = 1, C = 0, D = -5$

$Amplitude = | A | = 5$ $"Amplitude " = |A| = 5$

$Period = \frac{2 π}{| B |} = 2 π$ $"Period " = (2pi) / |B| = 2pi$

$Phase Shift = - \frac{C}{B} = 0$ $"Phase Shift " = -C / B = 0$

$Vertical Shift = D = - 5$ $"Vertical Shift " = D = -5$

graph{(-5) cos (x) - 5 [-10.67, 9.33, -6.92, 3.08]}

How do you graph r=5−5cosθr=5-5costheta?