How do you graph #r=5 sec θ#? Trigonometry The Polar System Graphing Basic Polar Equations 1 Answer Cesareo R. May 31, 2016 The straight #x = 5# Explanation: Here #r cos(theta) = 5->x=5#. The graphic is the straight #x = 5# Answer link Related questions What are limacons and cardioids? How do you graph basic polar equations? How do you determine the shape of a limaçon from the polar equation? How do you graph #r = 1.5#? How do you graph #\theta = 30^\circ#? What does the graph of #r = \cos \theta# such that #0^\circ \le \theta \le 360^\circ# look like? What is the general form of limacons and cardioids and how do you graph transformations? How do you graph the equation #r = 1 + cos( theta )#? How do you graph #r=3-2costheta#? How do you graph #r=1-cosx#? See all questions in Graphing Basic Polar Equations Impact of this question 10677 views around the world You can reuse this answer Creative Commons License