How do you graph $r=2+costheta$ ?

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Answer 1 · 2016-08-15T09:22:25

The graph is r-oscillation, withe period $2pi$ , about the circle r = 2, in the range $r in [1, 3]$ ..

The Table for one period, for $theta = 0 (pi/4) 2pi$ ::

$(r, theta): (3, 0) (2+1/sqrt 2, pi/4) (2, pi/2) (2-1/sqrt 2, 3/4pi)$

$(1, pi) (1+1/sqrt 2, 5/4pi) (2, 3/2pi) (2+1/sqrt 2, 5/4pi) (3, 2pi)$ 1,

How do you graph r=2+costhetar=2+costheta?