How do you graph r(2cosθ)=2?

1 Answer
May 3, 2016

In Catrersian form it is 3x2+4y24x4=0 an ellipse.

Explanation:

If (r,θ) is in polar form and (x,y) in Cartesian form the relation between them is as follows:

x=rcosθ, y=rsinθ, r2=x2+y2 and tanθ=yx

Or, cosθ=xr, sinθ=yr, θ=tan1(yx) and cotθ=xy.

Hence, r(2cosθ)=2 can be written as

2rrcosθ=2

2(x2+y2)12x=2 or

2(x2+y2)12=2+x or

4(x2+y2)=(2+x)2 or

4x2+4y2=4+x2+4x or

3x2+4y24x4=0

As coefficients of x2 and y2 are both positive but not equal, this is an ellipse.

The above can be written as

3(x243x+49)+4y241290

or 3(x23)2+4(y0)2=489=163

or 916(x23)2+34(y0)2=1

or (x23)2169+(y0)243=1

Center of ellipse is (23,0)

Major axis is 2×43=83 and minor axis is 2×23=43

graph{3x^2+4y^2-4x-4=0 [-3, 3, -1.5, 1.5]}