How do you graph $r=2(1-sin(theta))$ ?

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Answer 1 · 2016-11-22T16:33:45

See the cardioid in the inserted graph.

graph{x^2+y^2-2sqrt(x^2+y^2)+2y=0 [-10, 10, -5, 5]}

The genera equation of the cardioid is

$r=a(1+cos(theta-alpha))$ , with cusp at the pole and axis of

symmetry, along the radial line $theta=alpha$

Here a = 2 and $alpha = -pi/2$ .

How do you graph r=2(1-sin(theta))r=2(1-sin(theta))?