How do you graph $θ = - \frac{5 π}{6}$ $theta=-(5pi)/6$ ?

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How do you graph $θ = - \frac{5 π}{6}$ $theta=-(5pi)/6$ ?

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Answer 1 · 2018-01-30T18:00:08

If you are using polar graph paper, then you place your straight edge over the origin and rotate it clockwise $\frac{5 π}{6} radians$ $(5pi)/6" radians"$ (this will place it at the angle $\frac{7 π}{6}$ $(7pi)/6$ ) and draw a straight line.

If you are using Cartesian graph paper, then plot the line

$y = tan (- \frac{5 π}{6}) x$ $y = tan(-(5pi)/6)x$

$y = \frac{\sqrt{3}}{3} x$ $y = sqrt3/3x$

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How do you graph $θ = - \frac{5 π}{6}$ $theta=-(5pi)/6$ ?

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How do you graph $θ = - \frac{5 π}{6}$ $theta=-(5pi)/6$ ?