How do you graph $r = 6 + 6 cos θ$ $r=6+6costheta$ ?

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Answer 1 · 2016-10-11T20:27:10

graph{6+6cos x [-14.13, 14.36, -1.17, 15]}

Hopefully you know what the graph of $y = cos θ$ $y=cos theta$ looks like:
graph{cos x [-14.13, 14.36, -7.17, 7.05]}

The the graph of $y = 6 cos θ$ $y=6cos theta$ is that graph stretched along Oy by factor 6:
graph{6cos x [-14.13, 14.36, -7.17, 7.05]}

Finally, the graph of $y = 6 + 6 cos θ$ $y=6+6cos theta$ is that graphed moved up alonmg Oy 6 units
graph{6+6cos x [-14.13, 14.36, -1.17, 15]}

How do you graph r=6+6cosθr=6+6costheta?