How do you graph $r = \frac{1}{{(cos t)}^{2}}$ $r=1/((cos t)^2)$ ?

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Answer 1 · 2016-07-01T09:11:21

$1 \leq r < \infty$ $1 <=r< oo$ ,.

As $t \to \frac{π}{2} or \frac{3 π}{2}, r \to \infty$ $t to pi/2 or (3pi)/2, r to oo$ .

The graph is symmetrical about $θ = 0, \frac{π}{2} . π and \frac{3 π}{2}$ $theta=0, pi/2. pi and (3pi)/2$ (both x and y axes)

Rightly, the graph is asymptotic to these directions and the radial

lines $θ = \frac{π}{2} and θ = \frac{3 π}{2}$ $theta=pi/2 and theta=(3pi)/2$ (y-axis, both ways) are not

asymptotes.

The graph cuts the initial line $θ = 0$ $theta=0$ at (1, 0).

Elsewhere, $r > 1 .$ $r>1.$ .

The graph looks like a hyperbola, near the pole..

How do you graph r=1/((cos t)^2)r=1(cost)2r=1/((cos t)^2)?