How do you graph $r=3/sin(theta)$ ?

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Answer 1 · 2017-08-02T21:22:49

The easiest way to graph the equation is to observe that it converts to $y = 3$ using the following steps:

$r = 3/sin(theta)$

$rsin(theta)=3$

$y = 3$

This is a horizontal line at $y = 3$

If you want to stay with polar coordinate system, avoid division by 0 and a negative radius by adding the restriction:

$r = 3/sin(theta); 0 < theta < pi$

Then start plotting points:

$(3,pi/2)$ , $(6,pi/6)$ , $(6,5pi/6)$

If you connect these 3 points, you will see that it is a horizontal straight line segment.

How do you graph r=3/sin(theta)r=3/sin(theta)?