How do you graph $r = 3 sec (theta + 90°)$ ?

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Answer 1 · 2016-10-16T02:00:55

Draw the straight line parallel to the compounded initial line $theta= 0 and theta = pi$ , at a distance 3. in the direction $theta = 3/2pi$ .

This is the polar form for $y = -3$

Here, $r = 3sec(theta+ 90^o)=3(-csc theta)=-3/sin theta$

So, y = r sin theta = -3

Draw the straight line parallel to the compounded initial line $theta= 0 and theta = pi$ , at a distance 3. in the

direction $theta = 3/2pi$ .

How do you graph r = 3 sec (theta + 90°)r = 3 sec (theta + 90°)?