How do you graph $r = 3sin ((theta) + pi/4)$ ?

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Answer 1 · 2016-03-09T04:45:16

Draw circle with center at $(3/2, 3pi/4)$ and radius $3/2$ .

The general equation of a circle with center at $(d/2, pi/2+alpha) and radius=d/2$ is
$r=d sin (theta+alpha)$ .

Here, d =3 and $alpha=pi/4$ . The circle passes through r = 0. d is diameter of the circle.

Make a table $(r, theta)}, theta=0,pi/4,pi/2,3pi/4,pi,5pi/4,3pi/2,5pi/4 and 2pi$ , and mark the points on the circle.

How do you graph r = 3sin ((theta) + pi/4)r = 3sin ((theta) + pi/4)?