Question

How do you graph `3=rcos(theta-pi/3)`?

Answer 1

See explanation

Explanation:

`r = p sec (theta - alpha ) rArr p = r cos ( theta - alpha )`

represents the straight line through `N( p, alpha )`, perpendicular

to ON.

Here, N is ( 3, pi/3 ), distant r = 3 from O, in the direction

`theta = alpha = pi/3 = 60^o`.

I think, this is sufficient, for making the graph..

See the graph, with the dot at N..
graph{ (x+y sqrt3 -6)((x-1.5)^2+(y-1.5sqrt3)^2-0.02) = 0[0 10 0 5]}