How do you graph $r=-3sintheta$ ?

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Answer 1 · 2017-02-08T11:24:27

See graph.
graph{x^2+y^2+3y=0 [-8, 8, -4, 4]}

As $r(costheta, sintheta)=(x,y)$ ,

$r^2=x^2+y^2=-3rsintheta=-3y$ , giving

$x^2+(y+3/2)^2=(3/2)^2$ representing the circle,

with center $C(0, -3/2)$ and radius $a = 3/2$ .

Now, make Socratic graph

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How do you graph r=-3sinthetar=-3sintheta?