How do you graph #r=-3sintheta#?

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Answer 1 · 2017-02-08T11:24:27

See graph.
graph{x^2+y^2+3y=0 [-8, 8, -4, 4]}

As #r(costheta, sintheta)=(x,y)#,

#r^2=x^2+y^2=-3rsintheta=-3y#, giving

#x^2+(y+3/2)^2=(3/2)^2# representing the circle,

with center #C(0, -3/2)# and radius #a = 3/2#.

Now, make Socratic graph

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