This is based on the balanced reaction:
#HC-=CH(g) +2H_2(g)#
#rarr H_3C-CH_3(g)#.
Thus one mole of ethyne (#"C"_2"H"_2#) requires two moles of hydrogen. Given equiv temperature and pressure for a reaction between (essentially ideal) gases, the same volume ratio applies. Thus #0.25*dm^3# acetylene clearly requires #0.50*dm^3# dihydrogen gas for stoichiometric equivalence.
Note that #1" dm"^3=(10^-1" m")^3 =10^-3" m"^3=1" L"#.