How do you write an equation of a line given point (-4,6) and m=8?

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Answer 1 · 2016-09-01T02:57:43

The equation for the given condition is:
$y$ $-$ $8x$ $=$ $38$

The general equation of a line is given by:
$y$ $=$ $m*x$ $+$ $c$ ;or
This is when you have the $Slope$ $(m)$ and the $Intercept$ $(c)$ given.

If you have a point $(X,Y)$ as in this case and the $slope$ $(m)$ , the general form is:
$(y-Y)$ = $m$ $*$ $(x-X)$

So, for point $(-4,6)$ and slope $m$ $=$ $8$ , this gives
$(y-6)$ $=$ $8$ $*$ $(x-(-4))$ ;or

$(y-6)$ $=$ $8$ $*$ $(x+4)$ ;or

$(y-6)$ $=$ $8x$ + $32$ ;or

$y$ $-$ $8x$ $=$ $38$