How do you find the definite integral for: $xdx$ for the intervals $[12, 14]$ ?

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Answer 1 · 2016-10-04T23:11:26

$26$ square units

$int_12^14xdx=[x^2/2]_12^14=14^2/2-12^2/2=196/2-144/2=52/2=26$

$26$ square units

How do you find the definite integral for: xdxxdx for the intervals [12, 14][12, 14]?