How do you find the vertex of #f(x)=3x^2-25#?

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Answer 1 · 2016-10-07T19:55:47

#Vertex => (x,y) => (0,-25)#

Standard form of a quadratic equation

#ax^2+bx+c=0#

#x=-b/2a#

#y=f(-b/(2a))#

#Vertex => (x,y) => (-b/(2a),f(-b/(2a)))#

#f(x)=3x^2-25=3x^2+0x-25#

#a=3#
#b=0#
#c=-25#

Substitute

#x=-b/(2a)=-0/(2(3))=0#

#y=f(-b/(2a))=f(0)=3(0)^2-25=0-25=-25#

#Vertex => (x,y) => (0,-25)#

Click on the video below to learn about several methods of finding the vertex of a quadratic equation.