How do you find the indefinite integral of $\int - 6 x d x$ $int -6x dx$ ?

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Answer 1 · 2016-10-21T08:56:16

$\int - 6 x d x = - 3 x^{2} + c$ $int-6xdx=-3x^2+c$

$\int - 6 x d x = - \frac{6 x^{2}}{2} + c = - 3 x^{2} + c$ $int-6xdx=-(6x^2)/2+c=-3x^2+c$

$\int x^{n} d x = \frac{x^{n + 1}}{n + 1}$ $intx^ndx=x^(n+1)/(n+1)$

How do you find the indefinite integral of ∫−6xdxint -6x dx?